reena is6 years older than her brother ajay. the sum of their ages is 28 years. what are their present ages

Ajay's age = x years

Reena's age = x + 6 years

Sum of their ages = 28 yrs

So, we have

x + (x + 6) = 28  …………….(i)

2x + 6 = 28

2x = 28 - 6

2x = 22

x = 11

Thus, Ajay's age 11 yrs.

Reena's age = x + 6 = 11 + 6 = 17 yrs

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Let Reena's age be x

Ajay's age=x+6

sum of their age=28

x+x+6=28

2x+6=28

2x=28-6

2x=22

x=22/2

x=11

Reena's age=11

Ajay's age=11+6=17

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