let Ve be the escape velocity..and Vo is the orbital velocity,then

VE^{2}= 2gR_{E}

VO^{2}= gRE , where R_{E}is the radius of the earth.

==) VE^{2}= 2 VO^{2}

^{ or}

^{ VE = root 2 Vo}

this means the square of escape velocity is equivalent to twice the square of orbital velocity.....

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escape velocity is the minimum speed needed for an object to "break free" from the gravitational attraction of a massive body. The escape velocity from Earth is about 40,270 km/h (25,020 mph). The velocity of this orbit depends on the distance from the object to the center of the Earth

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Escape velocity is minimum velocity with which a body should be projected so that it just escapes the earth's gravitational field whereas orbital velocity is velocity with which satellite revolve around the earth or the velocity required to put the satellite into its orbit around the earth.

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