Relative decrease in vapour pressure of an aqueous solution containing 2 mol [Cu(NH3 )3 Cl] Cl in 3 mol H2 - Chemistry - Solutions

Question

Relative decrease in vapour pressure of an aqueous solution
containing 2 mol [Cu(NH3 )3 Cl] Cl in 3 mol H2 O in 0 50 On
reaction with AgNO3 , this solution will form
(a) 1 mol AgCl
(b) 0 25 mol AgCl
(c) 2 mol AgCl
(d) 0 40 mol AgCl

Yasodharan · Accepted Answer

Dear Student,

The calculation are expressed as below,

Relative lowering in vapour pressure,∆ppo=inBinB+nA+
∆p=po-pFor AgCl = 3 mol - 2 mol = 1 mol AgClAnswer is Option (A) 1 mol AgCl

Regards

Relative decrease in vapour pressure of an aqueous solution containing 2 mol [Cu(NH3 )3 Cl] Cl in 3 mol H2 O in 0.50. On reaction with AgNO3 , this solution will form (a) 1 mol AgCl (b) 0.25 mol AgCl (c) 2 mol AgCl (d) 0.40 mol AgCl

Relative decrease in vapour pressure of an aqueous solution containing 2 mol [Cu(NH3 )3 Cl] Cl in 3 mol H2 O in 0.50. On reaction with AgNO3 , this solution will form
(a) 1 mol AgCl
(b) 0.25 mol AgCl
(c) 2 mol AgCl
(d) 0.40 mol AgCl