Represent the following in polar form

1/1+i

Here we will first rationalise the denominator as;
$$\begin{gathered} \frac{1}{1+i} \\ = \frac{1}{\left(1+i\right)}\times \frac{\left(1-i\right)}{\left(1-i\right)} \\ = \frac{1-i}{1^2-i^2} \\ = \frac{1-i}{1-{\left(-1\right)}^2} \{\mathrm{since}; i^2 = -1\} \\ = \frac{1}{2}\left(1-i\right) \end{gathered}$$
Now for further clarification, you can follow the same procedure as given in the link shown below:
https://www.meritnation.com/ask-answer/question/convert-the-given-complex-number-in-polar-form-1-i/complex-numbers-and-quadratic-equations/6321719

Still if you have any doubt then please do get back to us.