Rs 10,000 is invested at 5% interest rate p.a. Find the interest at the end of one year.

The formula to find the interest is PxTxR divided by 100. So, here we do

Interest=10,000x5/100

=50,000/100

=Rs.500

Therefore, the interest at the end f the year is Rs.500.

  • 10
For a principal 100=5% & 10,000=? Multiply the number 10,000 to the number top cross it and divide with the number right at the top of it. =10,000×5/100 = 50000/100 = 500 Now multiply this number with the time. =500×1 =500 Therefore, Rs 500 is the interest at the end of 1 year.
  • 4
5000
  • 2
10500
  • -1
Please find this answer

  • -1
$500
  • 1

The formula to find the interest is PxTxR divided by 100. So, here we do

Interest=10,000x5/100

=50,000/100

=Rs.500

Therefore, the interest at the end f the year is Rs.500.

  • 2
Ko8bn
  • -2

interest=100p∗r∗t​

p = principal amount , r = rate , t = time
interest=10010000∗5∗1​
interest = RS. 500

i hope this helps

  • 1
Yesdsss
  • 1
Answer = Rs 500
  • 1
rs.500
  • 0
10500
  • 0
WHAT
  • 0
10500
  • 0
Tehgsh
  • 0
Rs 500
  • 1
5/100*10000=interest
=5/1*100
=500 rupees
therefore 5 rupees is the interest of one year
  • 0
YO!
principal=rs 10000
Time=1yr
rate=5% p.a 
S.I= P*r*t/100
S.I=10000*5*1/100

S.I= 100*5*1
SI= rs 500
Amount=principal+S.i

Amount=10000+500
Therefore, Amount is rs 10500
Thanks :) o^o
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