Rs.427.50 was paid as interest on Rs.3050.If the rate was 6%p.a and the amount was borrowed on January 10,2001 , what was the date on which the loan was recovered?

Dear Student,


Simple Interest=PRT100427.50=3050×6×T100427.50=305×6×T10427.50=1830×T10427.50=183×TT=427.50183conerting it into number of daysT=427.50183×365=852.66 days or we can say 853 daysthe  number of days in 2 years =2×365=730Hence till january 10, 2003 are coveredremaining days=853-730=123jan 10 +123 days21 days in jan, 28 days in feb, 31 days in march+30 days in apr+13 days in mayHence loan was recovered on 13th May 2003.
Regards,

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