Sanjari Kalantari ma'am, I think that the solution you provided me before some time ,is incomplete... So, please recheck ... The solution is not providing a final value or answer. Please re solve. 
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Sanjari Kalantari ma'am, I think that the solution you provided me before some time ,is incomplete... So, please recheck ... The solution is not providing a final value or answer. Please re solve.  ​ EXPERT ANSWER Sanjari Kalantri , Meritnation expert added an answer 53 seconds ago Dear Student, Let us assume that the amount Ryan had to withdraw is a 4 — digit number. Also, let a be the digit in the thousands place, b in the hundreds place, c in the tens place and d in the ones place. So, the amount he had to withdraw = 1000a + 100b + IOC + d. Now, Ryan wrote the last two digits in place of the first two digits, and first two digits in place of the last two digits in the cheque. In other words, he wrote c in the thousands place, d in the hundreds place, a in the tens place and b in the ones place. So, the amount he actually withdrew 1000c + 100d + 10a + b. Now, Ryan brought a 5 rupees pouch with the withdrawn money. So, the amount now left with 5. Ryan now realised that the actual amount he should have written in the cheque is twice the amount left with him. 980a + 98b 1990c — 199d + 10 The above equation s This conversation is already closed by Expert 10 Was this answer helpful? @ (C) 0