sathish sold a camera to rajesh at a profit of 10 %.rajesh sold it to john at a loss of 12%. if john paid Rs. 4,840,at what price did sathish buy the camera?
Let us assume that the Cost Price of the camera which Rajesh paid to Satish be Rs. x.
Selling Price of the camera by Rajesh = Rs. 4840.
As we know tha Loss% = (Cost Price - selling Price) / Cost price x 100
12 = (x - 4840)/x x 100
12x = 100x - 484000
12x - 100x = - 484000
- 88x = - 484000
x = 484000/88 = Rs. 5500.
So the Cost Price of Rajesh will be the selling price of Satish, which is equal to Rs. 5500.
Again let us assume that Satish brougth the camera at a cost of Rs. y.
As we know thet Profit% = (Selling Price - Cost price) / Cost Price x 100
10 = (5500 - y) / y x 100
10y = 550000 - 100y
10y + 100y = 550000
110y = 550000
y = 550000/110 = Rs. 5000.
Ans: Rs. 5000.