sec A + tan A=3 Sin A + cos A= - Maths - Trigonometric Functions

Question

sec A + tan A=3
​Sin A + cos A=??

Ghanshyam Dhakar · Accepted Answer

Dear
student,
We have,secA+tanA=3⇒secA=3-tanA⇒sec2A=3-tanA2use sec2x = 1+tan2x1+tan2A=9-6tanA+tan2A6tanA  = 8tanA = 43then sinA = 432+42=45, cosA = 332+42=35sinA+cosA  =45+35 =75
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sec A + tan A=3 ​Sin A + cos A=??

sec A + tan A=3
Sin A + cos A=??