Section C no 13 13 â ‹ABCD is a rectangle X and Y are points on - Maths - Congruence of Triangles

Question

Section C no 13

13 â€‹ABCD is a rectangle
X and Y are points on side AD and BC respectively such that AY = BX
Prove that AX = BY

Sanjari Kalantri · Accepted Answer

Dear Student,

Given: ABCD is a rectangle, AY = BXTo prove: AX = BYProof: Since, ABCD is a rectangle, ∠XAB = ∠YBA = 90° - iIn ∆AXB and ∆BYA,AY = BX   GivenAB = AB   Common∠XAB = ∠YBA = 90°    From i∴ By SAS congruence criterion,∆AXB ≅ ∆BYABy corresponding parts of congruent triangles (cpct),AX = BYHence, proved

Section C no 13 13. ​ABCD is a rectangle. X and Y are points on side AD and BC respectively such that AY = BX. Prove that AX = BY.

Section C no 13

13. ABCD is a rectangle. X and Y are points on side AD and BC respectively such that AY = BX. Prove that AX = BY.