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x^2 = 100
so,
x = root 100 = 10
now,
x^2-x 
=100-10
=90
  • -4
x= 100
(x)2= (10)2
x=10

x2-x= 100-10 = 90
  • -2
X^2=100. So obviously X=10. So now X^2-X=100-10=90
  • 0
x=100
x=+-10
CASE I: If x=+10
x2-x = 100-(+10)
       = 100-10
       = 90
CASE II: If x=-10
x2-x = 100-(-10)
       = 100+10
       = 110
 
  • 0
X^2=100
Sq. rooting both sides
? (X^2)=? (100)
X=+-10
X^2-X=100-(+-10)
Case 1. X=+10
X^2-X
=100-10
=90

Case 2. X=-10
X^2-X
=100-(-10)
=100+10
=110
  • 0
Answer 90
  • -4
100-10=90
  • -4
90...is answer
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90 ans So simple Question
  • -4
All the above solutions are half correct. Always remember that x^2 - x has degree 2 and hence, it is a quadratic equation. A quadratic equation always has two solutions and so never stop thinking when you have reached a single solution but hunt for the second solution. Here, x = 90 or 110.

  • -1
If, x^2=100 X=10 X^2-X=100-10=90
  • -1
Answer is 90.

  • -1
Answer is 90

  • -2
X^2-x=90.i hope it is correct.
  • -2
90 hoga
  • -1
X^2=100 X=+10/-10 X^2-X=100-(10/-10) =100-10/100+10 =90/110
  • 1
hello friends,

  • 1
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