Shape of SF4, SiCl4, NO+2, PH3, BrF3
Dear student,
The shape of SiCl4 molecule is perfect tetrahedral with the hybridisation of Si as sp3. The shape of SF4 is see saw geometry with hybridisation of S as sp3d . The shape of BrF3 is T shape and hybridisation of Br as sp3d. The shape of PH3 cannot be explained on the basis of hybridisation theory since in this molecule, the bond angles come close to 90. According to Drago rule, the hydrogen is unable to contract the orbitals of Phosphorus to take part in hybridisation and bonding takes place by overlapping of pure P orbitals and hence the angle is close to 90.
The shape of NO+2 is linear and cannot be explained on the basis of hybridisation or VSEPR theory and can only be explained via Molecular Orbital theory.
Hope this helps,
Regards
The shape of SiCl4 molecule is perfect tetrahedral with the hybridisation of Si as sp3. The shape of SF4 is see saw geometry with hybridisation of S as sp3d . The shape of BrF3 is T shape and hybridisation of Br as sp3d. The shape of PH3 cannot be explained on the basis of hybridisation theory since in this molecule, the bond angles come close to 90. According to Drago rule, the hydrogen is unable to contract the orbitals of Phosphorus to take part in hybridisation and bonding takes place by overlapping of pure P orbitals and hence the angle is close to 90.
The shape of NO+2 is linear and cannot be explained on the basis of hybridisation or VSEPR theory and can only be explained via Molecular Orbital theory.
Hope this helps,
Regards