show root 31 on number line.

Answer:
We can draw $\sqrt{31}$ on number line by using Pythagoras theorem As :

$\sqrt{31}$  = $\sqrt{{\left(4\right)}^2 + {\left(\sqrt{15}\right)}^{ 2} }$  For getting $\sqrt{15}$ first we draw square root spiral till we get $\sqrt{15}$ ( We can get value of ​

$\sqrt{31}$ by spiral but as we know after $\sqrt{17}$ it's overlap its previous lines so for simplification we break $\sqrt{31}$ into two parts )

After getting $\sqrt{15}$ on the spiral we take that length make perpendicular of that length on the ' 4 ' , As we get our

hypotenuse $\sqrt{31}$  , Now take that length of ​$\sqrt{31}$  and make an arc on the number line , where that intersect our

number line that represent $\sqrt{31}$  As :