show that : (2sinx - sin2x) / (2sinx + sin2x) = tan^2 (x/2) Share with your friends Share 0 Anuradha Sharma answered this Taking LHS, 2sinx-sin2x2sinx+sin2x=2sinx-2sinxcosx 2sinx+2sinxcosx=2sinx 1-cosx2sinx 1+cosx= 1-cosx 1+cosx= 1-1-2sin2x2 1+2cos2x2-1=sin2x2cos2x2=tan2x2 10 View Full Answer Debdutta Biswas answered this LHS = 2sinx(1 - cosx)/2sinx(1 + cosx) = (1 - cosx)/(1 + cosx)now use the formula cosx = (1 - tansquarex/2)/(1 + tansquarex/2 and simplify.you will arrive at tansquarex/2 -4
