# show that current leads the voltage in phase by pie/2 in an ac circuit containing an ideal capacitor

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• 8
In a circuit having capacitor,
q/C=V=Vosin(wt)............
On differentiating wrt time,
dq/dt=i=CVow cos(wt)=C​Vow sin( pi/2 + w)=isin( pi/2 + w)
Thus it leads the voltage in phase by pi/2

• -4

@ gauri

for that u need to be cleared about the derivation of capacitive circuit ..

as u knws

I = dq/dt = d/dt (cv)

as q=cv

so, we can write cv as c e0 sin w t

by integrating that

we get

I= CE0 d/dt (sin wt )

by keeping ce0 as constant ..

so.

I= CE0 COS WT / W

I= E0/1/WC COS WT

SO, U CAN WRITE THE ABOVE EXP AS

I= I0 SIN (WT+PIE/2 )

so, from the above exp its conformed that current leads voltage by phase of pie/2

HOPE IT HELPS

CHEERS

• 1
Refer to ncert for 12th part 2 page no.238
• 4
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