Login

show that current leads the voltage in phase by pie/2 in an ac circuit containing an ideal capacitor

Dear Student,
Kindly refer to the link given below for an answer to a similar query.
https://www.meritnation.com/ask-answer/question/a-sinusoidal-emf-is-applied-to-a-circuit-containing-capacita/physics/6298301

Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.







 

  • 9
View Full Answer
In a circuit having capacitor,
q/C=V=Vosin(wt)............
On differentiating wrt time,
dq/dt=i=CVow cos(wt)=C​Vow sin( pi/2 + w)=io sin( pi/2 + w)
Thus it leads the voltage in phase by pi/2
 
  • -4

@ gauri 

for that u need to be cleared about the derivation of capacitive circuit ..

as u knws 

I = dq/dt = d/dt (cv) 

as q=cv 

so, we can write cv as c e0 sin w t 

by integrating that 

we get 

I= CE0 d/dt (sin wt ) 

by keeping ce0 as constant ..

so. 

I= CE0 COS WT / W 

I= E0/1/WC COS WT 

SO, U CAN WRITE THE ABOVE EXP AS 

I= I0 SIN (WT+PIE/2 ) 

so, from the above exp its conformed that current leads voltage by phase of pie/2 

 

HOPE IT HELPS 

CHEERS

  • 1
Refer to ncert for 12th part 2 page no.238
  • 4
What are you looking for?