show that current leads the voltage in phase by pie/2 in an ac circuit containing an ideal capacitor
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for that u need to be cleared about the derivation of capacitive circuit ..
as u knws
I = dq/dt = d/dt (cv)
so, we can write cv as c e0 sin w t
by integrating that
I= CE0 d/dt (sin wt )
by keeping ce0 as constant ..
I= CE0 COS WT / W
I= E0/1/WC COS WT
SO, U CAN WRITE THE ABOVE EXP AS
I= I0 SIN (WT+PIE/2 )
so, from the above exp its conformed that current leads voltage by phase of pie/2
HOPE IT HELPS