show that current leads the voltage in phase by pie/2 in an ac circuit containing an ideal capacitor

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  • 8
In a circuit having capacitor,
q/C=V=Vosin(wt)............
On differentiating wrt time,
dq/dt=i=CVow cos(wt)=C​Vow sin( pi/2 + w)=isin( pi/2 + w)
Thus it leads the voltage in phase by pi/2
 
  • -4

@ gauri 

for that u need to be cleared about the derivation of capacitive circuit ..

as u knws 

I = dq/dt = d/dt (cv) 

as q=cv 

so, we can write cv as c e0 sin w t 

by integrating that 

we get 

I= CE0 d/dt (sin wt ) 

by keeping ce0 as constant ..

so. 

I= CE0 COS WT / W 

I= E0/1/WC COS WT 

SO, U CAN WRITE THE ABOVE EXP AS 

I= I0 SIN (WT+PIE/2 ) 

so, from the above exp its conformed that current leads voltage by phase of pie/2 

 

HOPE IT HELPS 

CHEERS

  • 1
Refer to ncert for 12th part 2 page no.238
  • 4
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