Show that following points are vertices of a square:
(0,1) , (1,4) , (4,3) , (3,0).

Let A0,1; B1,4; C4,3; D3, 0 are the given points.Now, we know that distance between points x1, y1 and x2, y2 is given bydistance = x2 - x12 + y2 - y12Now, AB = 1-02 + 4-12 = 12 + 32 = 1+9 = 10 unitsNow, BC = 4-12 + 3-42 = 32 + -12 = 9+1 = 10 unitsNow, CD = 3-42 + 0-32 = -12 + -32 = 1+9 = 10 unitsNow, DA = 0-32 + 1-02 = -32 + 12 = 9+1 = 10 unitsNow, AC = 4-02 + 3-12 = 16 + 4 = 20 = 25 unitsNow, BD = 3-12 + 0-42 = 4+16 = 20 = 25 unitsSo, in quadrilateral ABCD, we have,AB = BC = CD = DA   and AC = BDSo, given quadrilateral is a square.We know that a quadrilateral is a square, if each of its sides are equal and also its diagonals are equal.

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Expert please answer.
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let these points form a quadrilateral ABCD
here A ( 0,1)    B (1,4)    C ( 4,3)   D ( 3,0)

properties of a square =  all sides are equal and all diagnols are equal

length of side ab = root 10 ( by applying distance formula)
length of side bc = root 10 ( by applying distance formula)
length of side cd = root 10 ( by applying distance formula)
length of side ad = root 10 ( by applying distance formula )

length of diagonal ac = root 20 ( by applying distance formula ) 
length of diagonal bd = root 20 ( by applying distance formula )

as all the sides and both the diagonals of the quadrilateral are equal , hence it is a square
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