Show that P-7, P-10, P-13, P-16, P- 19,....... are in A.P. find its 8th term and it's common difference.
T2 - T1 = P-10 - P + 7 = -3
T3 - T2 = P-13 - P + 10 = -3
=> Difference is equal
=> It is an AP
Now,
a = P-7 and d = -3
8th term = a + 7d
= P-7 + 7(-3)
= P - 7 - 21
= P - 28