Show that the relation (R) defined by (a,b)R(c,d) -> a+d=b+c on the set N X N is an equivalence relation Share with your friends Share 5 Aakash Sharma answered this Dear Student! @nikitha : Good Effort! Keep Posting! Cheers! -10 View Full Answer Nikitha Sreekumar answered this For every element (a,b) belongs to NxN(a,b)R(a,b) implies a+b=b+a (which is true)Hence R is reflexiveLet (a,b)R(c,d) implies a+d=b+c " b+c=a+d " c+b=d+a " (c,d)R(a,b)Hence R is symmetricLet (a,b)R(c,d) and (c,d)R(e,f)implies a+d=b+c and c+f=d+e" a+d+c+f=b+c+d+e" a+f=b+e" (a,b)R(e,f)Hence R is transitive Hence R is an equivalence relation 9