Show that the square of the period of revolution of satellite is direct proportional to the cube of radius of orbit. Please! Answer stepwise.

We know, orbital velocity of satellite is given by where G is gravitational constant, M is mass of earth and r is the radius of circular orbit. but we know, when a particle moves in circular path of radius r, then orbital velocity of the particle is given by , , here T is time period. squaring both sides, here it is clear that e.g., the square of the period of revolution of a satellite is directly proportional to the cube of the orbital rahttps://brainly.inore