show that the value of tan x/ tan 3x wherever it is defined never lies between 1/3 and 3 . Share with your friends Share 3 Lovina Kansal answered this Dear student y=tanxtan3x=tanx3tanx-tan3x1-3tan2x=tanx1-3tan2x3tanx-tan3x=1-3tan2x3-tan2x ∵tan3x≠0⇒3x≠0⇒x≠0⇒tanx≠0Let tanx =ty=1-3t23-t2⇒3y-t2y=1-3t2⇒3y-1=t2y-3t2⇒3y-1=t2y-3⇒t2=3y-1y-3⇒3y-1y-3≥0,t2≥0 ∀t∈R⇒y∈-∞,13∪3,∞Therefore, y is not defined in between 13,3 Regards 3 View Full Answer
