Show that x^3++αx^2+βx+gamma will be a perfect cube when α^2=27(gamma) and 3α(gamma)=β^2 - Maths - Complex Numbers and Quadratic Equations

Question

Show that x^3++αx^2+βx+gamma will be a perfect cube when
α^2=27(gamma) and 3α(gamma)=β^2

Samrat Dutta Roy · Accepted Answer

Dear Student,

Here, some assumptions are made (reasons given) If the assumptions are not upto the mark then feel free to post a clearer question in a different thread so that we can reach out our helping hands to clear your doubts Regards