Simplify : [(1-x2)/( x3+1)] X [(1-x2)/(1-x)2]

1-x2x3+1×1-x21-x2= 1-x1+xx3+1×1-x1+x1-x2    {using the identity a2-b2 = a-ba+b}= 1-x1+x×1-x1+x1+xx2-x+1×1-x2          {Using the identity a3+b3 = a+ba2-ab+b2}= 1+xx2-x+1

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