Dear student, The given surds are 23×34 The orders of the given surds are 3 and 4 and L C M of 3 and 4 is 12 23 = 213=2412=2412=161234 = 314=3312=3312=2712Therefore,23×34 = 1612 × 2712 = 16×2712=43212 Regards,

simplify ∛2×∜3

Dear student,

The given surds are \sqrt[3]{2} \times \sqrt[4]{3} . The orders of the given surds are 3 and 4 and L . C . M . of 3 and 4 is 12 . \sqrt[3]{2} = 2^{\frac{1}{3}} = 2^{\frac{4}{12}} = \sqrt[12]{2^{4}} = \sqrt[12]{16} \sqrt[4]{3} = 3^{\frac{1}{4}} = 3^{\frac{3}{12}} = \sqrt[12]{3^{3}} = \sqrt[12]{27} Therefore, \sqrt[3]{2} \times \sqrt[4]{3} = \sqrt[12]{16} \times \sqrt[12]{27} = \sqrt[12]{16 \times 27} = \sqrt[12]{432}

Regards,

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simplify ∛2×∜3​

simplify ∛2×∜3