(sin^2(2x)+ 4sin^4x - 4sin^2x cos^2x)/4-sin^2(2x) - 4sin62x = 1/9 find value of x - Maths - Trigonometric Functions

Question

(sin^2(2x)+ 4sin^4x - 4sin^2x cos^2x)/4-sin^2(2x) - 4sin62x = 1/9
find value of x

Chandan chaurasiya · Accepted Answer

(sin^2(2x)+ 4sin^4x - 4sin^2x.cos^2x)/4-sin^2(2x) - 4sin62x = 1/9 find value of x.