sin(2 cos inverse (-3/5)) =

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Please find below the solution to the asked query:

We have:sin2cos-1-35We know cos53=35cos180-53=-cos53cos180-53=-35180-53=cos-1-35sin2cos-1-35=sin2180-53=2sin180-53.cos180-53  sin2A=2sinA.cosA=2sin53-cos53=2×45×-35=-2425 Answer
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  • -2
This question can be solved as follows:-   
       sin(2 cos-1(-3/5))
=>  sin(2 cos-1(3/5))              [cos-1(-x) = cos-1(x)]
=>  sin(2 * 530)         [cos-1(3/5) = 530 by considering a right triangle with base 3, hypotenuse 5 and base angle 530]
=>  2*sin(530)*cos(530)
=>  2*(4/5)*(3/5)
=>  24/25
  • -1
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