sin(2 cos inverse (-3/5)) =

Dear Student,
Please find below the solution to the asked query:

We have:sin2cos-1-35We know cos53=35cos180-53=-cos53cos180-53=-35180-53=cos-1-35sin2cos-1-35=sin2180-53=2sin180-53.cos180-53  sin2A=2sinA.cosA=2sin53-cos53=2×45×-35=-2425 Answer

Hope this information will clear your doubts about this topic.

If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.

  • -2
This question can be solved as follows:-   
       sin(2 cos-1(-3/5))
=>  sin(2 cos-1(3/5))              [cos-1(-x) = cos-1(x)]
=>  sin(2 * 530)         [cos-1(3/5) = 530 by considering a right triangle with base 3, hypotenuse 5 and base angle 530]
=>  2*sin(530)*cos(530)
=>  2*(4/5)*(3/5)
=>  24/25
  • -1
What are you looking for?