(sin 20/cos 20)^2+ ( cos 62 / sin 28)- sin^2 30 Share with your friends Share 0 Neha Sethi answered this Dear student sin20°cos20°2+cos62°sin28°-sin230°=sin20°cos20°2+sin90°-62°sin28°-122 cosx=sin90°-x=sin20°cos20°2+sin28°sin28°-14 =sin20°cos20°2+1-14=tan220°+34 Regards 0 View Full Answer