(sin^3 theta - Cos^3 theta) / (sin theta - Cos theta) Share with your friends Share 0 Varun.Rawat answered this sin3θ - cos3θsin θ - cos θ=sin θ - cos θsin2θ + cos2θ - sin θ . cos θsin θ - cos θ=sin2θ + cos2θ - sin θ . cos θ=1 - sin θ . cos θ 0 View Full Answer Aditya Chauhan answered this 1+(sin theta*cos theta) -3 Aditya Chauhan answered this since,(sin^3 theta - cos^3 thaeta) = (sin theta - cos theta)(sin^2 theta + cos^2 theta +(sin theta * cos theta) (sin theta - cos theta) (sin theta - cos theta) -1 Muskan answered this Quite easy Huh? 1 Rohinth Ram R.v. answered this =1 -1
Quite easy Huh?