sin(theta) = perpendicular/ hypotenuse

sin( 90 degree) = 1

But we know that hypotenuse is the longest side in a right triangle.

Then how can ' perpendicular/ hypotenuse ' be equal to '1 ' ?

Question

sin(theta) = perpendicular/ hypotenuse
sin( 90 degree) = 1
But we know that hypotenuse is the longest side in a right
triangle
Then how can ' perpendicular/ hypotenuse ' be equal to '1 '
?

Ayush Jha · Accepted Answer

We know that,

$\sin θ = \frac{P e r p e n d i c u a r}{H y p o t e n u s e} \sin 90^{0} = 1$

As the $θ$ tends to right angle than the perpendicular becomes equal to the hypotenuse,

You told the correct thing that hypotenuse is the longest side but $θ$ approaching to right angle is the limiting situation and at this situation perpendicular becomes equal to the hypotenuse.

sin(theta) = perpendicular/ hypotenuse sin( 90 degree) = 1 But we know that hypotenuse is the longest side in a right triangle. Then how can ' perpendicular/ hypotenuse ' be equal to '1 ' ?

sin(theta) = perpendicular/ hypotenuse

sin( 90 degree) = 1

But we know that hypotenuse is the longest side in a right triangle.

Then how can ' perpendicular/ hypotenuse ' be equal to '1 ' ?