# Sir can you explain me this? I did'n understood. Dear Student,

mass of bullet= 10g = 0.01 kg
velocity of bullet= 1.5 m/s
mass of plank= 90g = 0.09kg
Total momentum before collision= mass of plank x velocity

Total momentum after collision = (mass of bullet +mass of plank)x velocity

According to law of conservation of momentum,
Total momentum before collision=Total momentum after collision

velocity acquired by the plank and the bullet =

Regards

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?

dubeyvijay1508

22.07.2017

Physics

Secondary School

+5?pts

A bullet having a mass of 10g and moving with a speed of 1.5 m/s,penetrates a thick wooden plank of mass 90g. The plank was initially at rest. The bullet gets embedded in the plank and both move together.Determine their velocity.

1

Me???Beginner

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Given :?
mass of bullet= 10g= 0.01kg
velocity of bullet= 1.5m/s
mass of plank= 90g=0.09kg
Total momentum before collision=mass of plank x velocity
=0.01x1.5+0.09x0=0.015 kgm/s
Total momentum after collision=(mass of bullet +mass of plank )x velocity
=0.1 kg x V=0.1 V kgm/s
According to law of conservation of momentum,
Total momentum before collision=Total momentum after collision
0.015kg m/s =0.1 v kg m/s
Thus,velocity acquired by the plank and the bullet = 0.15m/s
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