Sir/Madam can you please solve question no. 11
Hi Bishakha, sin ϕ = opp / hyp = 5/13
And tan θ = opp / adj
= 12/(14 - 5) = 12/9 = 4/3
Now AD cos θ = 9
SO AD = 9/cos θ = 9 sec θ
And tan θ = opp / adj
= 12/(14 - 5) = 12/9 = 4/3
Now AD cos θ = 9
SO AD = 9/cos θ = 9 sec θ