Sir plz tell only by method of elimination of substitution

 

0.2x+0.1y=25...(i)
2(x−2)−16y=116...(ii)
By solving (ii) eq.
2x−4−16y=116
2x−1.6y=120
x−0.8y=60×2
0.2x+0.1y=25×8
⇒x−0.8y=60
1.6x+0.8y=200
2.6x=260
x=2600​/216
x=100
∴0.2(100)+0.1y=25
20+0.1y=25
0.1y=5
y=00