sir Share with your friends Share 0 Shruti Tyagi answered this Dear student, The expansion of x+ynx+yn=C0nxn y0+C1nxn-1y1+C2nxn-2y2+......+Cn-1nx1yn-1+Cnnx0yn ..(1)Given series is C0np+C1npq+C2npq2+......+CnnpqnTaking p common=pC0n+C1nq+C2nq2+......+Cnnqn =p1+qn ...[ from (1) ] Hence option 1 is the answer Regards 0 View Full Answer