Six coins are tossed simultaneously. Find the probability of getting:

1. 3 heads

2. No heads

3. atleast one head


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1.probability of getting three heads=C(6,3)*(1/2)^3 *(1/2)^3=5/16.

2.PROBABILITY OF GETTING NO HEAD=(1/2)^6=1/64.

3.PROBABILITY OF GETTING ATLEAST ONE HEAD=1-(PROBABILITY OF GETTING NO HEAD)=1-1/64=63/64

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