six wires of current I1 = 1A , I2 = 2A, I3 = 3A , I4 = 1A , I5 = 5A and I6 = 4A cut the page perpendicularly the points 1,2,3,4,5 and 6 respectively as shown in the figure. Find the value of the integral B?dl around the closed path.
Dear student,
From Ampere circuital law , the line integral of magnetic field around the closed loop is equal to times the algebraic sum of current passing through loop.
As wire 5 is outside loop hence we have to consider other 5 wires.
Net current of other wire is
Hence the value is given by
Regards.
From Ampere circuital law , the line integral of magnetic field around the closed loop is equal to times the algebraic sum of current passing through loop.
As wire 5 is outside loop hence we have to consider other 5 wires.
Net current of other wire is
Hence the value is given by
Regards.