solid NH4HS(s) dissociates to give NH3(g) and H2 (G) and is allowed to attain equilibrium at 100 c . if the value of Kp for its dissociation is found to be 0.34 , find the total pressure at equillibrium and partial pressure of each component

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NH4HS (s)     NH3(g) +  H2S(g)      Kp =(pNH3)(pH2S) and, pNH3=pH2S=xTherefore, Kp=x2or, x=Kp=0.34=0.583 Total pressure at equilibrium = pNH3+pH2S = 0.583+0.583=1.16

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