Solubility product of silver chloride is 10 to the power -15. Calculate its molar solubility.

Ksp=10-15

AgCl <---> Ag+  +Cl-

Ksp=[Ag+][Cl-]

Let

Ag+ = x

Then Cl-= x

So that

X^2=10-15

X= 3.16*10-8

  • -10
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