Dear Student LHS: (4ax+3y)2-(4ax-3y)2 Since (A+B)2=A2+2AB+B2 and (A-B)2=A2-2AB+B2Opening the brackets:(4ax)2+(3y)2+2×4ax×3y-((4ax)2+(3y)2-2×4ax×3y)16a2x2+9y2+24axy-(16a2x2+9y2-24axy)16a2x2+9y2+24axy-16a2x2-9y2+24axy48axy=RHSHence Proved We hope that this answer solves your query Regards

Solution of 6B

Dear Student.

L H S : {(4 a x + 3 y)}^{2} - {(4 a x - 3 y)}^{2} S i n c e {(A + B)}^{2} = A^{2} + 2 A B + B^{2} a n d {(A - B)}^{2} = A^{2} - 2 A B + B^{2} O p e n i n g t h e b r a c k e t s : {(4 a x)}^{2} + {(3 y)}^{2} + 2 \times 4 a x \times 3 y - ({(4 a x)}^{2} + {(3 y)}^{2} - 2 \times 4 a x \times 3 y) 16 a^{2} x^{2} + 9 y^{2} + 24 a x y - (16 a^{2} x^{2} + 9 y^{2} - 24 a x y) 16 a^{2} x^{2} + 9 y^{2} + 24 a x y - 16 a^{2} x^{2} - 9 y^{2} + 24 a x y 48 a x y = R H S H e n c e P r o v e d

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