Solution of differential equation Cos y log (sec x + tan x) dx= Share with your friends Share 0 Neha Sethi answered this Dear studentThe given equation is:cosy logsecx+tanxdx=cosx logsecy+tanydysecx logsecx +tanxdx=secy logsecy+tanydyIntegrating both sides12log secx+tanx2=12logsecy+tany2+c' as ∫secxdx=logsecx+tanx and ddx logsecx+tanx=secxor logsecx+tanx2= logsecy+tany2+c Regards 2 View Full Answer Sibi answered this -sin y . log(sec x + tan x ) + 1/sec x + tan x * (secx tanx +sec2x).cos y -1
