solution please
Dear student
Please ask question one by one. Here I am answering the question no. 15.
First, let us calculate the number of atoms present in the given sample of sulphur.
no of moles = given mass/ molar mass = 3.2/32 = 0.1 mole
No. of atoms = 0.1* 6.023*1023 = 6.023 * 1022.
Now we know the no. of atoms in the given sample of Sulphur. To find the moles of Calcium with equal atoms,
we need to divide the obtained result by Avogadro's constant = 6.023 * 1022/ 6.023 * 1023 = 0.1
now, we know the no. of moles of calcium,
0.1 = w/40
w = 4
So 4g of Calcium will have the same number of atoms as 3.2g of Sulphur.
Regards
Please ask question one by one. Here I am answering the question no. 15.
First, let us calculate the number of atoms present in the given sample of sulphur.
no of moles = given mass/ molar mass = 3.2/32 = 0.1 mole
No. of atoms = 0.1* 6.023*1023 = 6.023 * 1022.
Now we know the no. of atoms in the given sample of Sulphur. To find the moles of Calcium with equal atoms,
we need to divide the obtained result by Avogadro's constant = 6.023 * 1022/ 6.023 * 1023 = 0.1
now, we know the no. of moles of calcium,
0.1 = w/40
w = 4
So 4g of Calcium will have the same number of atoms as 3.2g of Sulphur.
Regards