Solve 1.ii and iii

Dear Student,

Please find below required solution
1 (ii) Principal = 6750 , Rate = $9\frac{1}{3}\% = \frac{28}{3}\%$ per annum
        and time = 3 years and 2 months 
        12 months = 1 year
         so 1 month = $\frac{1}{12}$years and 2 months = $2 \times \frac{1}{12}=\frac{2}{12}=\frac{1}{6}years$
so time = 3 years and 2 months = 3 + $\frac{1}{6}=\frac{19}{6 }years$ 

$$\begin{gathered} Simple interest = \frac{Principal \times rate \times time}{100} \\ =\frac{6750 \times {\displaystyle \raisebox{1ex}{$28$}\!\left/ \!\raisebox{-1ex}{$3 $}\right.}\times {\displaystyle \raisebox{1ex}{$19$}\!\left/ \!\raisebox{-1ex}{$6$}\right.}}{100}=\frac{6750 \times 28\times 19}{100\times 3\times 6}=1995 \\ so simple interest = Rs 1995 \\ and amount = principal+ S.I = 6750 +\hspace{0.17em}1995 =Rs 8745 \end{gathered}$$

iii )  Given that  rate of interest for 1 month = 0.5%
 so simple interest earned in 1 month = 0.5% of principal = 0.5 * 14320 /100 = 71.6
so interest earned in 1year 3 months that is in 15 months = 15 *  71.6 =  Rs 1074
so SI = 1074 and Amount = principal + SI = 14320 + 1074 = Rs 15394.

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