solve 19 and 23 no.

solve 19 and 23 no. 5 m by 4 m by 20 cm. If the students can it Ibic metres of air on is a and the volume 'n a wooden box know the exact eadth 40 cm and de 40 cm would "w areas of area of the original new cubes y g. Acubeof a metal of 6 an edge is melted and cast into a cuboid fieareaofaplayground is 4800m2. Find the cost •thgtavellcmdeep, if die gravel costs ? 260 per cubic metre. A field is 30 m long and 18 m broad. A pit 6 m long, 4 m wide and 3 m deep is dug out from the middle Of the field and the earth removed is evenly spread over the remaining area of the field. Find the rise in the level of the remaining part of the field in centimetres correct to two decimal places. A tectangular plot is 24 m long and 20 m wide. A cubical pit of edge 4 m is dug at each Of the four corners Of the field and the soil removed is evenly spread over the remaining part Of the plot. By what height does the remaining plot get raised? 2k inner dimensions Of a closed wooden box are 2 m, m and •75 m. The thickness of the wood is 2•5 cm. Find the cost Of wood required to make the box if 1 rn3 of wocki woo. A Cubical wooden box Of internal edge 1 m is made of 5 cm thick wood. The box is open at the top. If the wood costs Z 9600 per cubic metre, find the cost of the wood required to A square brass plate of side X cm is 1 mm thick and weighs 4725 g. If one cc of brass cubes whose edges are x an, 8 cm and 10 are melted and recast . at therap

23)  x = 400
  • 1
19.
area of the plot = 30 x 18 = 540 m2
top area of the pit = 6 x 4 = 24 m2
now, base area of the left over plot = 540 - 24 =516 m2

volume of the pit = 6 x 4 x 3 = 72 m3

now, volume of pit = volume of earth added over the plot = 72 m3

or, 72 = base area of the left over plot x height of earth
or, 72 = 516 x height of earth
or, height of earth = 72 / 516 = 0.139 =0.14 m
  • 1
hope this will help you

  • 0
What are you looking for?