Solve 2nd question

2. A cyclist driving at 5 ms–1, picks a velocity of 10 ms–1, over a distance of 50 m. Calculate (i) acceleration (ii) time in which the cyclist picks up above velocity. [(i) 0.75 ms–2 (ii) 6.67 ms–2
 

Dear Student,
2.
given,u=5m/sv=10m/ss=50mi)we know,2as=v2-u22×a×50=102-52100a=100-25=75acceleration,a=75100=0.75 m/s2ii)acceleration,a=v-utt=v-uat=10-575=6.67 sec
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Sorry by mistake I have posted this question
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