Solve :- **2x ^{2} - (3+7i) x - (3-9i) = 0 **

**ANURAG.**

We have 2*x*^{2} – (3 + 7*i*) *x *– (3 – 9*i*) = 0.

On comparing the given equation with the general form *ax*^{2} + *bx* + *c* = 0, we obtain

*a* = 2, *b* = – (3 + 7*i*), c = – (3 – 9*i*)

Substituting the values of *a, b, c* in

Now firstly find out .

Since 2ab = –30, *a* and *b* must be of opposite signs.

Substituting either of these values in (1), we get

Hence the roots of the given equation are

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