solve 31
Al+3 + 3e- ---> Al
Here we see that 1 mole of Al+3 ion gives, 3 moles of electrons.
1F = 9650C = electric charge per mole of electrons.
So, 1 mole (27 gm )of Al requires = 3 x 96500 C
So, o.9 X 10-3 Kg = 0.9 gm of Al will require = (3x 96500/27) x 0.9 = 9650 C of electricity.