solve 31

solve 31 The amount of electricity required to deposit 31. 0.9 g of aluminium when the electode reaction • mass ofAl 27) b) 1.93 x 104 C a) 9.65 x 103 C c) 9.65 x 104 c d) 4.34 x C 32. For an electrolytic solution of0.05 mol L-1 , the specific conductance has been found to be 0.0110 S cm-l. The molar conductance is

Al+3 + 3e- ---> Al

Here we see that 1 mole of  Al+3 ion gives, 3 moles of electrons.

1F = 9650C = electric charge per mole of electrons.

So, 1 mole (27 gm )of  Al requires = 3 x 96500 C 

So, o.9 X 10-3 Kg = 0.9 gm of Al will require = (3x 96500/27) x 0.9  =  9650  C of electricity.

 

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