Solve 33 no.
Q.33. Find 0 π 4 d x cos 3 x 2   sin   2 x .

I=0π41cos3x2 sin 2xdx=0π41cos3x2×2 sin x cos xdx=120π41cos3xsin x12 cos x12dx=120π41cos3xsin xcos x12 cos x12×cos x12dx=120π41cos4xtan x12 dx=120π4sec2x sec2xtan x12 dx=120π41+tan2x sec2xtan x12 dxLet tan x=tdt=sec2x dxI=12011+t2t12 dt=12011t12 dt+1201t2t12 dt=1201t-12dt+1201t32 dt=12×2t1201dt+12×25t5201=1+15=65

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