solve 48. 48. The oxidation number of O in the following OF2, Na2O2 and O2 are respectively a)+2,-2,-2 b)-2 in all c) +2,0,-2 d)+2,-1,0 Share with your friends Share 0 Geetha answered this The oxidation number of oxygen in OF2x+2 (-1) = 0x= +2The oxidation number of oxygen in Na2O2 is2 (+1) + 2x = 02x= -2x= -1The oxidation number of oxygen in O2 is2x=0Since oxygen in its elemental form is 0 Thus option d is correct. 0 View Full Answer