solve : 5(2x-7) -3 (2x+3)<_0 and 2x + 19<_ 6x+47 and represent the solution in number line. Share with your friends Share 2 Tanveer Sofi answered this The given system of inequation is52x-7-32x+3≤0 ..........i2x+19≤6x+47 ..........iiNow,for inequation i52x-7-32x+3≤0⇒10x-35-6x-9≤0⇒4x-44≤0⇒4x-44+44≤44 Adding 44 to both sides⇒4x≤44⇒x≤11 Dividing both sides by 4⇒x∈(-∞,11]Similarly, for in equation ii2x+19≤6x+47⇒19≤4x+47 Subtracting, 2x from both sides⇒19-47≤4x+47-47 subtracting 47 from both sides⇒-28≤4x ⇒ 4x≥-28⇒x≥-7 dividing both sides by 4 ⇒x∈[-7, ∞) Therefore, the solution sets of inequations i and ii are represented by first and second line respectively. Now the solution to the given system of inequation isx∈(-∞,11]∩[-7,∞)⇒x∈∈[-7,11]This is represented the third real line. 0 View Full Answer
