Solve a²+b²-c²-d²+2ab-2cd by factorisation

a2+b2-c2-d2+2ab-2cd=a2+b2+2ab-c2-d2-2cd                                               =a2+b2+2ab-c2+d2+2cd                                               =a+b2-c+d2                                               =a+b+c+da+b-c-d                    Use identity, x2-y2=x-yx+yHence, a2+b2-c2-d2+2ab-2cd=a+b+c+da+b-c-d 

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