Dear student,Q solve and check; x-56 - x-730 = 1- x5Sol x-56 - x-730 = 1- x5⇒5x-5-(x-7)30=5-x5⇒5x-25-x+730=5-x5⇒54x-18=30(5-x)⇒20x-90=150-30x⇒20x+30x=150+90⇒50x=240⇒x=24050⇒x=245Check; Put x=245x-56 - x-730 = 1- x5⇒245-56 - 245-730 = 1- 2455⇒24-2556-24-35530=1-2425⇒-130--11150=25-2425⇒-130+11150=125⇒ -5+11150=125⇒6150=125⇒125=125Therefore, the equality is true because both sides are equal Regards

solve and check

D e a r s t u d e n t, Q . s o l v e a n d c h e c k; \frac{x - 5}{6} - \frac{x - 7}{30} = 1 - \frac{x}{5} S o l . \frac{x - 5}{6} - \frac{x - 7}{30} = 1 - \frac{x}{5} \Rightarrow \frac{5 (x - 5) - (x - 7)}{30} = \frac{5 - x}{5} \Rightarrow \frac{5 x - 25 - x + 7}{30} = \frac{5 - x}{5} \Rightarrow 5 (4 x - 18) = 30 (5 - x) \Rightarrow 20 x - 90 = 150 - 30 x \Rightarrow 20 x + 30 x = 150 + 90 \Rightarrow 50 x = 240 \Rightarrow x = \frac{240}{50} \Rightarrow x = \frac{24}{5} C h e c k; P u t x = \frac{24}{5} \frac{x - 5}{6} - \frac{x - 7}{30} = 1 - \frac{x}{5} \Rightarrow \frac{\frac{24}{5} - 5}{6} - \frac{\frac{24}{5} - 7}{30} = 1 - \frac{\frac{24}{5}}{5} \Rightarrow \frac{\frac{24 - 25}{5}}{6} - \frac{\frac{24 - 35}{5}}{30} = 1 - \frac{24}{25} \Rightarrow \frac{- 1}{30} - \frac{- 11}{150} = \frac{25 - 24}{25} \Rightarrow \frac{- 1}{30} + \frac{11}{150} = \frac{1}{25} \Rightarrow \frac{- 5 + 11}{150} = \frac{1}{25} \Rightarrow \frac{6}{150} = \frac{1}{25} \Rightarrow \frac{1}{25} = \frac{1}{25} T h e r e f o r e, t h e e q u a l i t y i s t r u e b e c a u s e b o t h s i d e s a r e e q u a l . R e g a r d s

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