Solve and explain briefly with formula!!!

7. A current of 1 A is flowing in the sides of an equilateral triangle of side 4.5 × 10–2 m. Find the magnetic field at the centroid of the triangle. 

Dear student,

Answer magnetic feid at the centroid is given as B=3μ0I4πa(sinθ1+sinθ2)here θ1=θ2=60length =4.5×10-2ma =l2cot60 =4.5×10-223therefore B=3×10-7×1×234.5×10-2232=4×10-5TB=4×10-5 T
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